(1/n)^-9

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Solution for (1/n)^-9 equation: 


D( n )

n = 0

1/n = 0

n = 0

n = 0

1/n = 0

1/n = 0

1*n^-1 = 0 // : 1

n^-1 = 0

n naleu017Cy do O

n in (-oo:0) U (0:+oo)

(1/n)^-9 = 0

1*n^9 = 0 // : 1

n^9 = 0

n = 0

n in { 0} 

n belongs to the empty set

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